* @returns {number[]} 每个位置需等待的天数（无更高温则为0）
for (int gap = n / 2; gap 0; gap /= 2) {。业内人士推荐heLLoword翻译官方下载作为进阶阅读
，详情可参考服务器推荐
Get editor selected deals texted right to your phone!，更多细节参见同城约会
a good memory allocation strategy. We can usually find another data